Question #81db1
1 Answer
Nov 20, 2016
Explanation:
differentiate using the
#color(blue)"chain rule"# on each term.
#color(red)(bar(ul(|color(white)(2/2)color(black)([d/dxln(f(x))]=1/(f(x))xxf'(x))color(white)(2/2)|)))#
#d/dx(-5ln(2x+1))=-5. 1/(2x+1).d/dx(2x+1)#
#=-10/(2x+1)#
#"and " d/dx(-ln(2x))=-1/(2x).d/dx(2x)=-1/x#
#rArr-(10/(2x+1)+1/x)" is the derivative"#
