# Question #751d5

Mar 17, 2017

The ratio is $= 0.54$

#### Explanation:

Let

mass of plane $= m k g$

speed of plane $= v m {s}^{-} 1$

radius of circle $= r m$

The centripetal force is $F = \frac{m {v}^{2}}{r} N$

The weight of the plane $W = m g N$

The ratio

$\frac{F}{W} = \frac{m {v}^{2}}{r} \cdot \frac{1}{m g}$

$= {v}^{2} / \left(r g\right) = {650}^{2} / \left(80000 \cdot 9.8\right)$

$= 0.54$