Question #7b2a4

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Answer 1 · 2016-11-27T15:16:40

#(cotx /(1+csc x)) + sinx cscx#

#cotx=1/tanx=cosx/sinx#

#1+cscx=1+1/sinx=(sinx+1)/sinx#

#cscx=1/sinx#

#sinxcscx=cancel(sinx)1/cancel(sinx)=1#

#(cotx /(1+csc x)) + sinx cscx=#

#(cosx/sinx)/((sinx+1)/sinx)+1=#

#cosx/cancel(sinx) xx(cancel(sinx)(1))/(sinx+1)+1=#

#cosx/(sinx+1)+1=#

#(cosx+sinx+1)/(sinx+1)=#

#1+cosx/(sinx+1)#