Question #442a7

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Answer 1 · 2016-12-02T02:53:02

See explanation.

This question can be done by unitary method for better understanding.

Since there are 3 beats in 1 movement in first measure.

Therefore there are 1 beat in $1/3$ measures.

Therefore there are $x$ beats in $x/3$ measures.

Similarly there are $b$ beats in $b/4$ measures.

As per questions, 'at least' is used so total no of counted measures, $x/3 + b/4$ , could be equal or more than 446.

So $x/3 + b/4 >= 446$