Here radius of the circular turn #r=10m#

Speed of the car during turn #v=36"km/hr"=(36xx10^3m)/(3600s)=10m/s#

Let #m # represents mass of the bob of the pendulum suspended from the ceiling of the car then the magnitude of **pseudo force** acting on the bob will be same as the **centripetal force** on it during its motion in a circular path of radius #r # with speed #v#

During dynamic equilibrium let #T # be the tension on string and #theta# be the angle made by the string with the vertical.

#Tsintheta# will balance the weight of the bob #mg# and #Tcostheta# will be equal to centripetal force #(mv^2)/r#

So #Tsintheta=mg.......[1]#

where #g -> "acceleration due to gravity"=9.8m/s^2#

#Tcostheta=(mv^2)/r.........[2]#

Dividing [1] by [2] we get

#tantheta=(rg)/v^2=(10xx9.8)/10^2=0.98#

#=>theta=tan^-1(0.98)=44.42^@#