# Question #19097

Dec 2, 2016

Lithium bromide.

#### Explanation:

The first thing to notice here is that you're dealing with an ionic compound due to the fact that lithium is a metal and bromine is a nonmetal.

Lithium is located in group 1 of the periodic table, so it will form $1 +$ cations by losing $1$ electron. Bromine is located in group 17 of the periodic table, so it will form $1 -$ anions by gaining $1$ electron.

Now, the name of the cation is the same as the name of the neutral atom. On the other hand, the name of the atom that becomes an anion changes from bromine to bromide.

Your ionic compound will thus contain

• lithium cations, ${\text{Li}}^{+}$
• bromide anions, ${\text{Br}}^{-}$

The name of the ionic compound starts with the name of the cation and ends with the name of the anion, so you will have

$\text{LiBr } \to$ lithium bromide