Question #71966

1 Answer
Dec 4, 2016

The fish is lying 1m below the surface of water and bird is flying 12 m above the surface of water. The fish is viewing the bird in air from denser medium water of refractive index #mu=4/3#.

If the bird is viewed nomally by the fish then we know the following relation.

#mu="Apparent depth in air"/"Real depth in air"#

#=>4/3="Apparent depth in air"/(12m)#

#=>"Apparent depth in air"=4/3xx12m=16m#

So the fish will see the bird at a distance #17m# from it.