Question

Question #9e2d5

Answer 1

Given `sin(A + B)=sin A •cos B + cos A •sin B`

Putting `A=pi/4 and B=pi/3` in the given relation we get

`sin(pi/4+pi/3)=sin(pi/4)cos(pi/3)+cos(pi/4)sin(pi/3)`

`=>sin((7pi)/12)=1/sqrt2xx1/2+1/sqrt2xxsqrt3/2`

`=>sin(pi-(5pi)/12)=(sqrt3+1)/(2sqrt2)`

`=>sin((5pi)/12)=(sqrt3+1)/(2sqrt2)`