Question

Question #4b2cc

Answer 1

Considering the percentage of `HCl` solution as w/v the mass of `HCl` present in 1 liter solution is
`=(3g)/(100mL)xx1000mL=30g`

`=(30g)/(36.5g/"mol")~~0.82mol`

The equation of nutralisation reaction

`HCl+NaOH->NaCl+H_2O`

This equatiion reveals that the reactants interact in `1:1` mole ratio.

So `0.82 mol` HCl requires `0.82` mole NaOH for nutralisation.

So the mass of `NaOH` required for nutralisation is
`=0.82molxx40g/"mol"=32.8g`