# Question #faf24

Dec 11, 2016

#### Answer:

The reaction will form 36.6 g of sulfur dioxide.

#### Explanation:

Step 1. Start with the balanced equation.

$\text{2CO + S"→ "SO"_2 + "2C}$

Step 2. Calculate the moles of $\text{CO}$.

$\text{Moles of CO" = 32.0 color(red)(cancel(color(black)("g CO"))) × ("1 mol CO")/(28.01 color(red)(cancel(color(black)("g CO")))) = "1.142 mol CO}$

Step 3. Calculate the moles of ${\text{SO}}_{2}$

${\text{Moles of SO"_2 = 1.142 color(red)(cancel(color(black)("mol CO"))) × ("1 mol SO"_2)/(2 color(red)(cancel(color(black)("mol CO")))) = "0.5712 mol SO}}_{2}$

4. Calculate the mass of ${\text{SO}}_{2}$.

${\text{Mass of KCl" = 0.5712 color(red)(cancel(color(black)("mol SO"_2))) × ("64.06 g SO"_2)/(1 color(red)(cancel(color(black)("mol SO"_2)))) = "36.6 g SO}}_{2}$