Question #faf24

1 Answer
Dec 11, 2016

Answer:

The reaction will form 36.6 g of sulfur dioxide.

Explanation:

Step 1. Start with the balanced equation.

#"2CO + S"→ "SO"_2 + "2C"#

Step 2. Calculate the moles of #"CO"#.

#"Moles of CO" = 32.0 color(red)(cancel(color(black)("g CO"))) × ("1 mol CO")/(28.01 color(red)(cancel(color(black)("g CO")))) = "1.142 mol CO"#

Step 3. Calculate the moles of #"SO"_2#

#"Moles of SO"_2 = 1.142 color(red)(cancel(color(black)("mol CO"))) × ("1 mol SO"_2)/(2 color(red)(cancel(color(black)("mol CO")))) = "0.5712 mol SO"_2#

4. Calculate the mass of #"SO"_2#.

#"Mass of KCl" = 0.5712 color(red)(cancel(color(black)("mol SO"_2))) × ("64.06 g SO"_2)/(1 color(red)(cancel(color(black)("mol SO"_2)))) = "36.6 g SO"_2#