Question #8de97
2 Answers
Dec 10, 2016
That is not an identity.
Explanation:
Recall that
So, we can write
# = cot^2x/csc^2x#
Recall also that
This allows us to continue
# = (cos^2x/sin^2x)/(1/sin^2x)#
# = cos^2x/sin^2x * sin^2x/1#
# = cos^2x#
Which is not identically
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Dec 10, 2016
No. It is equal to
Explanation:
If we have
The same way,
This is equal to