# Question 8b38a

Aug 19, 2017

24000

#### Explanation:

There are ""_6C_3 = 20 ways of selecting 3 boys from the group of 6 boys.
There are ""_5C_2 = 10 ways of selecting 2 girls from the group of 5 girls.
Therefore, there are $\left({\text{_6C_3)*(}}_{5} {C}_{2}\right) = 200$ ways of selecting the children.

Once you have selected five children, there are 5! = 120# different orderings of those children.

Therefore, there are $200 \cdot 120 = 24 , 000$ ways to both select and order the children.