Question #ccc07

2 Answers
Dec 16, 2016

x-2y+6=0

Explanation:

The standard form of an equation of this type is ax+bx+c=0, where x and y are variables(not having fixed value) and a, b and c are integers(-3,-2,-1,0,1,2,3...).
But, in this question, we need to take y to the other side in order to leave only 0 on that side.
To do this, subtract y from both sides. This does not affect the equation.

y-y=1/2x+3-y
1/2x-y+3=0

Now, we have to convert 1/2 to an integer, and to do this we multiply it by 2. For the equation to remain unaffected, we have to multiply all terms with 2. So,

cancel(2)^1xx1/(cancel(2))x-2xxy+2xx3=2xx0
=>x-2y+6=0

This is the standard form of the equation.

Dec 16, 2016

-1x + 2y = 6

Explanation:

The standard form for a linear equation is:

Ax + By = C where A, B and C are integers.

Therefore, we must multiply each side of the given equation by -2 to eliminate the fraction and keep the equation balanced:

-2y = -2(1/2x + 3)

-2y = -1x - 6

Now we can isolate the x and y terms on one side of the equation:

1x - 2y = 1x - 1x - 6

1x - 2y = 0 - 6

1x - 2y = -6