Question #ccc07
2 Answers
Explanation:
The standard form of an equation of this type is
But, in this question, we need to take
To do this, subtract
#y-y=1/2x+3-y#
#1/2x-y+3=0#
Now, we have to convert
#cancel(2)^1xx1/(cancel(2))x-2xxy+2xx3=2xx0#
#=>x-2y+6=0#
This is the standard form of the equation.
Explanation:
The standard form for a linear equation is:
Therefore, we must multiply each side of the given equation by
Now we can isolate the