Question

Question #69a2e

Answer 1

Given `r^2 = theta`

The breaks into 3 equations depending on the value of x and y:

`x^2 + y^2 = tan^-1(y/x); x > 0, y > 0`

`x^2 + y^2 = pi + tan^-1(y/x); x < 0`

`x^2 + y^2 = 2pi + tan^-1(y/x); x > 0, y < 0`

`x = 0` when you choose `y = 0` but not the vice-versa.