A gas occupies a volume of 12.7*mL at 295*K in a piston; what volume will it occupy at 284*K?

We use old Charles' law.....${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$, which establishes the influence of absolute temperature on gaseous volume......
We solve for ${V}_{2} = {V}_{1} / {T}_{1} \times {T}_{2}$
$\frac{12.7 \cdot m L}{295 \cdot K} \times 284 \cdot K = 12.2 \cdot m L$