Question

A gas occupies a volume of `12.7*mL` at `295*K` in a piston; what volume will it occupy at `284*K`?

Answer 1

We use old Charles' law.....`V_1/T_1=V_2/T_2`, which establishes the influence of absolute temperature on gaseous volume......

Explanation:

We solve for `V_2=V_1/T_1xxT_2`

`(12.7*mL)/(295*K)xx284*K=12.2*mL`

AS expected, the volume is slightly reduced at slightly reduced temperature.