Question #dfbed

Question

2714 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-24T02:28:33

So, the dog will eat #(7+(7d)/3)# cans in #(3+d)# days.

Let #x# be the number of cans that can be eaten by it in #(3+d)# days.

Here the ratio number of cans #= 7:x#

The ratio of number of days #= 3:(3+d)#

Here the number of cans and days are in direct proportion.

#:. 7:x=3:(3+d)#

or, #7/x=3/(3+d)#

or, #3x=7(3+d) rarr# Cross multiply.

or, #3x=21+7d#

or, #(3x)/3=(21+7d)/3 rarr# Dividng both sides by 3.

or, #x=21/3+(7d)/3 rarr# Split RHS

or, #x=7+(7d)/3#

So, the dog will eat #(7+(7d)/3)# cans in #(3+d)# days.