For what value of #x# is #x/0 = 2/1# ?

1 Answer
Dec 29, 2016

Answer:

The left hand side of this equation is undefined, regardless of the value of #x#, so there are no solutions.

Explanation:

In the context of algebra, division should be the same as multiplication by the multiplicative inverse, but #0# has no multiplicative inverse. So division by #0# is undefined.

If #0^(-1)# were defined then:

#1 = 0*0^(-1) = 0/0 = (0+0)/0 = 0/0 + 0/0 = 0*0^(-1)+0*0^(-1) = 1+1 = 2#