Question #d03ef

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Answer 1 · 2016-12-28T04:22:44

Limit #rarr##(1/(x-2)- 4/(x^3-2x^2 ))#
=#(1/(x-2)-4/(x^2(x-2)) )## now; ##(1/(x-2))# common

hence
#1/(x-2)##(1-4/x^2)#

#1/(x-2)##(x^2/x^2-4/x^2)# (I took lcm here or else u can cross multiply)

now (#a^2-b^2)#=#(a-b)##(a+b)#

#(1/(x-2))##((x-2)#(x+2)#/(x^2))#

#(1/cancel(x-2))##((cancel(x-2))#(x+2))# /(x^2)#

now #(x+2)/x^2#

now as we cannot simplify it further

substitute limits =#((2)+2)#/#(2)^2#

hence answer =1