Question #e0a62

1 Answer
Aug 6, 2017

Answer:

I got #25m#

Explanation:

We could use the relationship from Kinematics:

#v_f^2=v_i^2+2ad#

that, with your data for the first part, gives:

#15^2=30^2+2a*75#

solving for #a#:

#a=-4.5m/s^2#

we use this acceleration in #v_f^2=v_i^2+2ad# again for the second part where the final velocity will be zero and initial #15m/s#:

#0^2=15^2-2*4.5*d#

#d=25m#