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Answer 1 · 2017-01-07T14:00:23

The balanced equation of the reaction for the preparation of ethyne (#C_2H_2#) by the action of water on #CaC_2# is as follows.

#CaC_2+H_2O->=Ca(OH)_2+C_2H_2#

As per above equation 1 mol #C_2H_2# is produced from 1 mol #CaC_2#.

Molar mass of #CaC_2=(40+2*12)=64g/"mol"#

The given amount of #CaC_2=20g=20/64mol=5/16mol#.

So the amount of ethyne #C_2H_2# produced #=5/16mol#.
The molar mass of ethyne #C_2H_2=2xx12+2xx1=26g/"mol"#.

So the mass of ethyne #C_2H_2# produced

#=5/16molxx26g/"mol"=8.125g#.