Question #7ca7c

1 Answer
Jan 8, 2017

#8,-6,0," undefined"#

Explanation:

#"(a) (f+g)(1) means evaluate f(x)+g(x) when x = 1"#

#"That is " (f(1)+g(1)#

From the above table for x = 1 , check along the row and read the values given for f(x) and g(x)

#x=1tocolor(red)(f(x)=7)" and " color(blue)(g(x)=1)#

#rArr(f+g)(1)=7+1=8#

#" (b) Similarly"#

#(fxxg)(-1)" This time we want the product of the functions when x = - 1"#

From the table for x = - 1 , check along the row and read the values.

#x=-1tocolor(red)(f(x)=3)" and " color(blue)(g(x)=-2)#

#rArr(fxxg)(-1)=3xx-2=-6#

#" (c) again similar to above"#

#x=3tocolor(red)(f(x)=9)" and " color(blue)(g(x)=9)#

#rArr(f-g)(3)=9-9=0#

#" (d) " x=0tocolor(red)(f(x)=5)" and " color(blue)(g(x)=0#

#rArr(f/g)(0)=5/0" which is undefined"#