# Question #34a5f

Jan 9, 2017

A mass of $\text{NaCl}$ of $29.2 \cdot g$ will result.

#### Explanation:

We need a stoichiometrically balanced equation. What does $\text{stoichiometric}$ mean? Essentially, it means $\text{garbage in equals garbage out}$.

$N a \left(s\right) + \frac{1}{2} C {l}_{2} \rightarrow N a C l \left(s\right)$

The reaction unequivocally shows that each mole of natrium metal gives necessarily one mole of sodium chloride salt.

$\text{Moles of sodium} = \frac{11.5 \cdot g}{22.99 \cdot g \cdot m o {l}^{-} 1} = 0.500 \cdot m o l$

And, therefore, AT MOST we can synthesize a mass of $0.500 \cdot \cancel{m o l} \times \left(22.99 + 35.45\right) \cdot g \cdot \cancel{m o {l}^{-} 1} = 29.2 \cdot g$.

What do the values $\left(22.99 + 35.45\right) \cdot g \cdot m o {l}^{-} 1$ represent? From where did I get them?