# Question #eae28

##### 1 Answer

Aug 27, 2017

#### Answer:

I get this.

#### Explanation:

The problem consists of sum of two pressures which the pump must create

- Pressure due to height of
#40 m# of water column - Pressure due to jet of water at a rate of
#5ms^-1#

For 1. Assuming unit area, Force

Pressure due

#40m# water column#P_1=mg=rhoxx"volume"xxg#

#P_1=1000xx(40xx1)xx9.81=392400pa#

For 2. Assumed area of the jet be unit area.

Speed of water outlet from jet

Total mass of water thrown out per sec

Pump must exert pressure to support weight of this additional column of water of unit area

For unit area of jet pressure

Total pressure of the pump