# Question #fcecb

The square root of $36 {x}^{5} {y}^{5}$
$\sqrt{36 {x}^{5} {y}^{5}} = \sqrt{{6}^{2} {x}^{4} {y}^{4} \left(x y\right)} = 6 {x}^{2} {y}^{2} \sqrt{x y}$