How many #"microns"# are in a #0.056915*m# length?

1 Answer
Jan 13, 2017

Answer:

#1*m-=10^6mum#, i.e. #mu=xx10^-6#

Explanation:

And thus #0.056915*m# #=# #(0.056915*cancelm)/(10^-6*cancelm*mum^-1)#

#=56195*(1)/(mum^-1)==56195*(1)/(1/(mum))=56195*mum.#

Note that when use a calculator (which of course I did!), when you put in the exponential #"1 exp 6"#, this is actually #1xx10^6#. Claro?