# How many "microns" are in a 0.056915*m length?

$1 \cdot m \equiv {10}^{6} \mu m$, i.e. $\mu = \times {10}^{-} 6$
And thus $0.056915 \cdot m$ $=$ $\frac{0.056915 \cdot \cancel{m}}{{10}^{-} 6 \cdot \cancel{m} \cdot \mu {m}^{-} 1}$
$= 56195 \cdot \frac{1}{\mu {m}^{-} 1} = = 56195 \cdot \frac{1}{\frac{1}{\mu m}} = 56195 \cdot \mu m .$
Note that when use a calculator (which of course I did!), when you put in the exponential $\text{1 exp 6}$, this is actually $1 \times {10}^{6}$. Claro?