Question #db044
2 Answers
Test the condition at the two limits given in the question,
I show you how, below...
Explanation:
The equation for a spherical mirror is
which I will write as
If the object is located at
This is only true if
Next, recall that for a spherical mirror,
The equation becomes
or
It follows (I think!) that for any placement of the object between these limits, the image must be between the location of
Assuming that the question is about spherical mirrors and has been posted under flat mirror by oversight only.
We know that Mirror formula is the relationship between object distance
#1/f=1/v+1/u# .....(1)
A. When Object is placed at
Object distance
Inserting in equation (1) we get
Implies that image is formed at
B. Object is placed at
Object distance
Inserting in equation (1) we get
Implies that image is formed at
C. Object is placed between
Object distance
Inserting in equation (1) we get
Inserting any value of
Note that for
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.
*Sign Convention: For spherical mirrors, normally object distance is taken as negative, as it is measured against direction of light.Image distance is positive for real images and is in the direction of travel of light. Focal length is positive accordingly for a converging mirror as it is measured in the direction of travel of light.
If sign convention is followed then Mirror Formula for a converging mirror becomes
#1/u+1/f=1/v#
and calculations are to be done appropriately.