Question

Question #2c01a

Answer 1

`lim_(x->0) sin^2x/x = 0`

Explanation:

Remebering that:

`lim_(x->0) sinx/x = 1`

`lim_(x->0) sin^2x/x = lim_(x->0) (sinx/x)*sinx = 1*0 =0`