Question #94bfd

1 Answer
Jan 21, 2017

Answer:

#1.73*mol*L^-1" with respect to sodium ion." #

Explanation:

We sum up the the total number of moles of #Na^(+)#.

#"Moles"# #=# #"concentration"# #xx# #"volume"#

#=25.0xx10^-3Lxx1.15*mol*L^-1+2xx25.0xx10^-3Lxx1.15*mol*L^-1=8.63xx10^-2*mol# with respect to sodium ion.

And this is dissolved in a volume of #50.0*mL#.

The new concentration is thus, #(8.63xx10^-2*mol)/(50.0*mL)=1.73*mol*L^-1# with respect to sodium ion.

Why did I multiply one of the starting concentrations by 2?