What is the concentration of potassium sulfate when a #0.65*mol# quantity is dissolved in #2.5*L# of aqueous solution?

1 Answer
Jul 30, 2017

Answer:

#[K_2SO_4]=0.26*mol*L^-1#

Explanation:

By definition, #"molarity"="Moles of solute"/"Volume of solution"#

And thus #[K_2SO_4(aq)]=(0.65*mol)/(2.5*L)=0.26*mol*L^-1#; what are the concentrations of this solution with respect to (i) #SO_4^(2-)# ion, and (ii) #K^+# ions?

What is the concentration with respect to potassium sulfate in #g*L^-1#?