Question

Question #c90a3

Answer 1

`4C_2H_3Cl_3+11O_2→ 8CO_2+ 6H_2O + 6Cl_2`

Above equation suggests that the `CO_2 and Cl_2` will be produced in the mole ratio `8:6=4:3`

So ratio of their masses will be
`=(4xx"molar mass of " CO_2)/(3xx"molar mass of "Cl_2)`

`=(4*44g"/mol")/(3*71g"/mol")`

`=176/213`

If xg `Cl_2` is produced on production of 59.5g `CO_2` then we can write
`59.5/x=176/213`

`=>x=(59.5xx213)/176g~~72g`