# How many quarts does a mass of 1.50xx10^3*g of ethanol represent?

Jan 23, 2017

Well, first we work out the volume of the ethanol.........and get an approximate volume of $2 \cdot \text{quart}$

#### Explanation:

$\text{Density, "rho="Mass"/"Volume}$.

And thus $\text{Volume}$ $=$ $\frac{\text{Mass}}{\rho} = \frac{1.50 \times {10}^{3} \cdot \cancel{g}}{0.79 \cdot \cancel{g} \cdot m {L}^{-} 1}$

$= 1898.7 \cdot m L = 1.899 \cdot L$ (this is consistent dimensionally, because the grams cancel out and we are left with units of $\frac{1}{\frac{1}{m L}} = m L$ as required.)

Now $\text{1 US quart} = 0.946 \cdot L$,

so (1.899*L)/(0.946*L*"quart"^-1)~="2 quart"