# Question #4c1b0

##### 1 Answer

Oct 1, 2017

#### Answer:

#### Explanation:

#"expand "f(x)=(x+3)^2-1#

#rArrf(x)=x^2+6x+9-1=x^2+6x+8#

#"the factors of + 8 which sum to + 6 are + 2 and + 4"#

#rArrx^2+6x+8=(x+2)(x+4)#

#f(x)=(x+3)^2-1=(x+2)(x+4)color(blue)" in intercept form"#