Question

Question #4c1b0

Answer 1

`f(x)=(x+2)(x+4)`

Explanation:

`"expand "f(x)=(x+3)^2-1`

`rArrf(x)=x^2+6x+9-1=x^2+6x+8`

`"the factors of + 8 which sum to + 6 are + 2 and + 4"`

`rArrx^2+6x+8=(x+2)(x+4)`

`f(x)=(x+3)^2-1=(x+2)(x+4)color(blue)" in intercept form"`