# Question #1e048

Jan 28, 2017

$= \left(x + 1\right) \left({x}^{4} + 1\right)$

#### Explanation:

There is no common factor which occurs in all the terms.

There are 4 terms, so group them into 2 pairs first.

$\left(\textcolor{red}{{x}^{5} + x}\right) + \left(\textcolor{b l u e}{{x}^{4} + 1}\right)$

$= \textcolor{red}{x \left({x}^{4} + 1\right)} + \left(\textcolor{b l u e}{{x}^{4} + 1}\right) \text{ } \leftarrow$ there is a common bracket

$= \left({x}^{4} + 1\right) \left(x + 1\right)$

$= \left(x + 1\right) \left({x}^{4} + 1\right)$

There are now 2 factors