Question

Question #4689b

Answer 1

We will try to rearragne the formula of the function.

Explanation:

`f(x)=x^2-2x+2=x^2-2x+1+1=(x-1)^2+1`

so first of all there are no constraints so the domain is : `D=x in RR`

now for the range,

`(x-1)^2>=0 iff (x-1)^2+1>=1 iff f(x)>=1 iff y>=1`

so the range is : `R=[1,+oo)`