# Question #6a4c5

Feb 4, 2017

${y}^{2} - 22 y + 121 = \left(y - 11\right) \left(y - 11\right)$

#### Explanation:

${y}^{2} - 22 y + 121$

By splitting the middle term i.e. -22 in such a way so, that the sum of those two numbers would be -22 and their product would be 121. Therefore, these two numbers are -11 and -11 . Here, both conditions are applied.

${y}^{2} - 11 y - 11 y + 121$

$y \left(y - 11\right) - 11 \left(y - 11\right)$

$\left(y - 11\right) \left(y - 11\right)$

Alternative Method:

${y}^{2} - 22 y + 121$

By using the identity -

$\left(a - b\right) \left(a - b\right) = {a}^{2} - 2 a b + {b}^{2}$

Here , $a = y , b = 11$

${\left(y\right)}^{2} - 2 \left(y\right) \left(11\right) + {\left(11\right)}^{2}$

$\left(y - 11\right) \left(y - 11\right)$