# Question #4c9d6

Feb 2, 2017

Titanium dioxide, titanium(IV) oxide.

#### Explanation:

You are dealing with an ionic compound that contains the cation of a transition metal, so right from the start, you should be aware that its name will include a Roman numeral that describes its oxidation state.

We use Roman numerals to describe the oxidation states of transition metals because these elements can have moe than one oxidation state.

Notice that one formula unit of this compound contains $2$ oxide anions, $2 \times {\text{O}}^{2 -}$.

This means that in order to balance the overall negative charge coming from the two oxide anions, the cation must carry a $4 +$ charge.

Therefore, you can say that this ionic compound contains titanium(IV) cations, ${\text{Ti}}^{4 +}$. The IV Roman numeral is used to show that the cation has a $+ 4$ oxidation state.

The name of the ionic compound will be

${\text{TiO}}_{2} \to$ titanium(IV) oxide

A more common name used for titanium(IV) oxide is

${\text{TiO}}_{2} \to$ titanium dioxide