How much iron metal can be produced from #40*g# #"ferric oxide"#?

1 Answer
Feb 2, 2017

Answer:

Approx.....#28*g# #"iron metal..............."#

Explanation:

We need (i), a stoichiometric equation that represents the iron reduction:

#2Fe_2O_3(s) + 6CO(s) rarr 4Fe +6CO_2(g)uarr#

And (ii) the equivalent quantity of #"ferric oxide"# that is reacted:

#=(40*g)/(159.69*g*mol^-1)=0.250*mol#

Given the equation, at most I can form #0.500*mol# #"iron metal"# #=# #0.500*molxx55.8*g*mol^-1=??g#