# How much iron metal can be produced from 40*g "ferric oxide"?

Feb 2, 2017

Approx.....$28 \cdot g$ $\text{iron metal...............}$

#### Explanation:

We need (i), a stoichiometric equation that represents the iron reduction:

$2 F {e}_{2} {O}_{3} \left(s\right) + 6 C O \left(s\right) \rightarrow 4 F e + 6 C {O}_{2} \left(g\right) \uparrow$

And (ii) the equivalent quantity of $\text{ferric oxide}$ that is reacted:

$= \frac{40 \cdot g}{159.69 \cdot g \cdot m o {l}^{-} 1} = 0.250 \cdot m o l$

Given the equation, at most I can form $0.500 \cdot m o l$ $\text{iron metal}$ $=$ 0.500*molxx55.8*g*mol^-1=??g