# Question #5d77a

If ${F}_{1} \mathmr{and} {F}_{2}$ are inclined at right angle and their resultant $R = 10 N$ makes ${30}^{\circ}$ with the directtion of ${F}_{2}$ ,then
${F}_{2} = R \cos {30}^{\circ} = 10 \times \cos {30}^{\circ} = 10 \times \frac{\sqrt{3}}{2} = 5 \sqrt{3} N$