Question #7adc3

1 Answer
Jim G.
Feb 11, 2017

#a=2" and " b=1#

Explanation:

#•f(1)=g(1)#

#rArr3/(a-b)=(a+b)/1#

#color(blue)"cross multiply"#

#rArr(a+b)(a-b)=3to(1)#

#•f(2).g(2)=4#

#rArr3/(2a-b)xx(2b+a)/1=4#

#rArr3(2b+a)=4(2a-b)#

#rArr6b+3a=8a-4b#

#rArr10b=5arArrcolor(red)(b=1/2a)#

Substitute #b=1/2a" into " (1)#

#rArr(a+b)(a-b)=3#

#rArra^2-b^2=3#

#rArra^2-(1/2a)^2=3#

#rArra^2-1/4a^2=3rArr3/4a^2=3#

#rArra^2=4rArra=+-2#

#a>0rArra=2#

#"and " b=1/2arArrb=1#

Related questions
See all questions in Function Composition
Impact of this question
1210 views around the world
You can reuse this answer
Creative Commons License