Question

Question #193f6

Answer 1

`CH_4`

Explanation:

Change the grams to moles

`(0.36 g H_2O)/(18 g//mol) = 0.02 mol H_2O`

`(0.44 g CO_2)/(44 g//mol) = 0.01 mol CO_2`

The ratio of water to carbon dioxide is 2: 1 so

`C_xH_y + z O_2 = 1 CO_2 + 2 H_2O` to balance the equation requires 1 C and 4 H's as well as 2.5 `O_2` so

`1 CH_4 + 2.5 O_2 = 1 CO_2 + 2 H_2O` or

`2 CH_4 + 5 O_2 = 2 CO_2 + 4 H_2O`

The compound is methane `CH_4`.