Question #c045e

1 Answer
Jul 8, 2017

Answer:

option (2)

Explanation:

#stackrel0Cl_2+stackrel(+1)Na stackrel(-2) O stackrel(+1)H->stackrel(+1)Na stackrel(+5)Clstackrel(-2)O_3+stackrel(+1)Na stackrel(-1)Cl+stackrel(+1)H_2stackrel(-2)O#

This is a disproportionation reaction where same element #Cl# gets oxidised as well as reduced.