# Question #43ea2

Feb 11, 2017

$\left(4 n - 3\right) \left(4 n + 3\right)$

#### Explanation:

This is a difference of squares. The identity states that:

${a}^{2} - {b}^{2} = \left(a - b\right) \left(a + b\right)$

We can rewrite the original expression as so:

$16 {n}^{2} - 9 = {4}^{2} {n}^{2} - {3}^{2} = {\left(4 n\right)}^{2} - {3}^{2}$

Then, use the identity to factor:

${\left(4 n\right)}^{2} - {3}^{2} = \left(4 n - 3\right) \left(4 n + 3\right)$