# How do you graph #y = sin(pi/2x + (3pi)/2)#?

##### 1 Answer

Jan 8, 2018

I'm assuming you want

#y = sin(pi/2x + (3pi)/2)#

In standard form. Use the sum formula for sine, which is

#y = sin(pi/2x)cos((3pi/2)) + cos(pi/2x)sin((3pi)/2)#

As long as you know you trigonometric function values at

#y = sin(pi/2x)(0) - 1(cos(pi/2x))#

#y = -cos(pi/2x)#

If you graph

Hopefully this helps!