# Question #a64bf

Feb 4, 2018

Dissolve $8.0 g$ of $N a O H$ in $100 m L$ water.
A "2-Molar Solution" is by definition 2 moles of a compound in 1 liter ($1000 m L$) of solvent. For sodium hydroxide ($N a O H$) one mole is 40 grams. Two moles is then 80g. If you only want 100mL, you only need $\frac{100 \text{mL}}{1000 m L} = 0.1$ as much,
or $0.10 \times 80 = 8 g r a m s$ of $N a O H$ in $100 m L$ of water.