# Question #21b57

Well, find me a transition metal that has four unpaired electrons in its five $\left(n - 1\right) d$ orbitals.
Did you choose tungsten ($\text{W}$)? If so, good choice, because its electron configuration for the valence electrons is $4 {f}^{14} \textcolor{b l u e}{5 {d}^{4}} 6 {s}^{2}$.
(If you picked $\text{Cr}$ or $\text{Mo}$, then you should review their electron configurations. They have $5$ unpaired $\left(n - 1\right) d$ electrons, and are notorious "exceptions" to so-called expected orbital filling orders.)
Verify that $\text{W}$ is an atom and that it is neutral.