# Question #b4c30

Apr 25, 2017

No solution.

#### Explanation:

$3 \left(1 - 2 x\right) > 3 - 6 x$

Expanding the left side, we get:

$3 - 6 x$

which is identical to the right side. So, for any value of $x$, the left side is identical to the right, i.e.

$3 \left(1 - 2 x\right)$ is never greater than $3 - 6 x$

:)>

Apr 25, 2017

This question is wrong!

#### Explanation:

To get rid of the 3 from $3 \left(1 - 2 x\right)$ divide both sides by 3

$\frac{3}{3} \left(1 - 2 x\right) \text{ ">" } \frac{3}{3} - \frac{6 x}{3}$

But $\frac{3}{3} = 1 \mathmr{and} \frac{6}{3} = 2$

$1 - 2 x > 1 - 2 x$

$\textcolor{red}{\text{There is something wrong with the question}}$