# Question #07b8f

##### 1 Answer

#### Explanation:

A solution's **molality** is simply a measure of how many moles of solute you get **for every** **solvent**.

In your case, a **moles** of barium chloride, your solute, for every

You can thus use the molality of the solution as a conversion factor to help you figure out how many moles of solute you need to have in

#250 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.250 kg"#

of water in order to have a

#0.250 color(red)(cancel(color(black)("kg water"))) * overbrace("3.0 moles BaCl"_2/(1color(red)(cancel(color(black)("kg water")))))^(color(blue)("= 3.0 m")) = color(darkgreen)(ul(color(black)("0.75 moles BaCl"_2)))#

The answer is rounded to two **sig figs**.