Question #9cb33

1 Answer
Feb 18, 2017

Answer:

Approx. #3.5*m^3#

Explanation:

We assume ideality, and calculate the volume occupied by an equivalent molar quantity of Ideal Gas.

Depending on your syllabus, they probably have #"STP"# #-=# #1*atm#, and #273.15*K#:

#V=(nRT)/P=((4300*g)/(28.05*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx273.15*K)/(1*atm)#

#=3.438xx10^3*L#.

I have always these types of question abstract where they ask the VOLUME occupied by a given quantity of gas at a given temperature. This assumes a scenario where the gas is introduced to an piston that can expand against #1# #"atm"#. The piston must be pretty big. Anyway, you can revise this answer depending on your given definition of #"STP"#.