Question #d6bdb

1 Answer
Jul 4, 2017

Answer:

The water displaced must have a mass of #9.25-8.2=1.05g#

Explanation:

This has a volume of #1.05cm^3#
(density is #0.998# at #20^o C#)

So the density of the metal is:
#rho(m)=m/V=9.25/1.05~~8.8g//cm^3#

The mass of the displaced gasoline was #9.25-8.36=0.84g#
#rho(g)=m/V=0.84/1.05~~0.80g//cm^3#

(everything rounded to 2 SF because of the #8.2#)