# Question #74471

$f \left(x\right) - 2 = \sqrt{x - 1}$
Hence $\sqrt{x - 1} \ge 0$ we have that
$f \left(x\right) - 2 \ge 0$ or $f \left(x\right) \ge 2$
Hence the range of $f \left(x\right)$ is $\left[2 , + \infty\right)$